3 Let’s use counters to solve the division 43 ÷ 2 as equal sharing.
There are two equal groups of 21 and a
10 10 10 10
1 1 1
remainder of 1. 43 ÷ 2 = 21 r 1
1
10 10
1
10 10
1
We can use what we know about part-whole relationships to help break the number 93 into parts that we can easily divide by 4. We divide 8 tens by 4 and then we
4
93 ÷ 4
80 ÷ 4 =
20
13 ÷ 4 =
3 r 1
23 r 1
divide 13 ones by 4. So, 93 ÷ 4 = 23 r 1
What is 74 divided by 6? We know that
1
× 6 = 60
more than 60.
74 is
We know that × 6 = so there is a remainder of
.
r
.
So 74 ÷ 6 =
198
9781380050687__text.indb 198
03/05/2022 10:20
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