DC Mathematica 2018

The light intensity c received from H is 1 ℎ 2 The light intensity c received from A and B is 1 2 + 1  2

ℎℎ  equal to 1 ℎ 2

Therefore, we can transfer a bulb at H to two bulbs at A and B.

5. Now we come to the most important part of the proof.

We firstly construct a circle, which has center  1 with

diameter 2 π

, then we construct a circle with diameter 4 π

which

centered at  2 , which is the opposite end of O of the

diameter.

We can place a bulb at  2 and do a horizontal line through

it which intersects with circle  2 at A and B. Connect OA

and OB. AS AB is diameter, ∠ AOB=90. Therefore, we

can replace the bulb at  2 with bulb at A and B. We can

continually do this step to infinite (double the radius and

replace the bulb)

Made with FlippingBook - professional solution for displaying marketing and sales documents online