U.S.TSUBAKI, INC.
Selection Procedure Example.
i) Confirm operating conditions for DOUBLE PLUS ® conveyor. Conveyor length: 30 ft. (9.14 m) Dimensions of conveyed object: 1.5 ft. (0.46 m) square Weight of conveyed object: 53 lbs. (24 kg)/piece 53 lbs./piece ÷ 1.5 ft. = 35.3 lbs./ft. (52.6 kg/m) Conveyed product speed: 30 ft./min (9.14 m/min). Chain speed: 12 ft./min. (3.66 m/min.) Full conveyor accumulating Quantity of conveyed object: 20 pieces Dry, in-plant use, normal operating temps (up to 77°F) ii) Select initial chain size. Using the calculation method in Section II. on page 12: T T = W T x (f 2 + f 3 ) x K T T = (35.3 lbs./ft. x 30 ft.) x (0.1 + 0.2) x 1.0 = 318 lbs. (144 kgf) T s = 318 lbs. x 0.6 = 190.8 lbs (86.5 kgf) Note: Presume two strands of chain, each loaded by 0.6 of the total. Based on these calculations, C2040VRP-A chain is the preliminary choice, but this selection must be confirmed. Note: C2040VRP-A weight/ft. = 0.67 lbs./ft. (1.0 kg/m) per strand [1.34 lbs./ft. (2.0 kg/m) for two strands]. iii) Confirm the maximum allowable roller load. By consulting Table 4a or 4b, you find that for C2040VRP-A, the maximum allowable roller load is 40 lbs./ft. (60 kg/m) for alu- minum rail. In this example, the weight of the conveyed object is 35.3 lbs./ft. (52.6 kg/m). Therefore, C2040VRP-A can cover roller load.
iv) Confirm total chain tension. Using the calculation method of total chain tension (T T ): T T = (0 + 1.34) x 0 x 0.08 + 35.3 x 30 x 0.10 + (35.3 + 1.34) x 30 x 0.20 + 1.1 x 1.34 x (0 + 30) x 0.08 T T = 329 lbs. (149 kgf) T S = T T x 0.6 = 197 lbs. (89 kgf) per strand Now determine chain size. Multiply the chain tension (T S ) by the chain speed coefficient (K) listed in Table 3, confirm with the following formula: T S x K ≤ Maximum allowable chain tension (Table 1a or 1b). 197 x 1.0 ≤ 200 (C2040VRP regular plastic) In this example, we would choose C2040VRP-A Chain.
v) Calculate required power. *Presume gearmotor efficiency ( ) = 0.8
329 lbs. x 12 ft./min. x 1.1 = 0.17 = 1/4 HP motor 33,000 x 0.8
HP =
149 kgf x 3.66 m/min. x 1.1 = .13 kW = 0.2 kW motor 6,120 x 0.8
kW =
• This calculation sample is for your reference only.
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