Mathematica 2015

So the latitude

πœ‘ ( 𝑖 ) = 90Β° βˆ’ 𝛼 ( 𝑖 ) + (𝑖 𝑖)

= 90Β° βˆ’ 50.308244597Β° + 12.8333333 == 51.875088736Β° = 51Β°52β€²30"

And we can calculate the longitude too:

Time difference to Greenwich: 11:53:31-12:00:00=-00:06:29=- 0.10805555555556 hours

Angular difference to Greenwich= -0.10805555555556*15=- 1.620833333334Β°=-1Β°37’15”

Longitude= result + equation of time for 22 nd April 2015 = -1Β°37’15”-1’26”=- 1Β°38’41”

Hence, according to my calculations, the Lab’s coordinates are:

51Β°52'30" N; 1Β°38’41” W

Whereas the actual ones are: 51Β°26’23”N 0Β°5’2”W (Google Maps).

I located the Lab… somewhere north-west of Oxford! Sir Ernest Shackleton OA would not be proud of me…

Figure 6: The location of our Lab (right pin) against my predictions (left pin).

Puzzle No.2

Use the numerals 1, 9, 9 and 6 exactly in that order to make the following numbers: 28, 32, 35, 38, 72, 73, 76, 77, 100 and 1000 You can use the mathematical symbols +, -, Γ—, /, √, ^ (exponent symbol) and brackets. Example: 63 = 1Γ—9+9Γ—6

32

Made with FlippingBook - Online Brochure Maker