Calculus Volume 1

142

Chapter 2 | Limits

Observe that for all values of x (regardless of whether they are approaching a ), the values f ( x ) remain constant at c .We have no choice but to conclude lim x → a c = c . The Existence of a Limit As we consider the limit in the next example, keep in mind that for the limit of a function to exist at a point, the functional values must approach a single real-number value at that point. If the functional values do not approach a single value, then the limit does not exist. Example 2.7 Evaluating a Limit That Fails to Exist

sin(1/ x ) using a table of values.

Evaluate lim x →0

Solution Table 2.5 lists values for the function sin(1/ x ) for the given values of x .

⎛ ⎝

⎞ ⎠

⎛ ⎝

⎞ ⎠

1 x

1 x

sin

sin

x

x

−0.1

0.544021110889

0.1

−0.544021110889

−0.01

0.50636564111

0.01

−0.50636564111

−0.001

−0.8268795405312

0.001

0.826879540532

−0.0001

0.305614388888

0.0001

−0.305614388888

−0.00001

−0.035748797987

0.00001

0.035748797987

−0.000001 0.349993504187

0.000001 −0.349993504187

Table 2.5 Table of Functional Values for lim x →0 sin ⎛ ⎝ 1 x

⎞ ⎠

After examining the table of functional values, we can see that the y -values do not seem to approach any one single value. It appears the limit does not exist. Before drawing this conclusion, let’s take a more systematic approach. Take the following sequence of x -values approaching 0: 2 π , 2 3 π , 2 5 π , 2 7 π , 2 9 π , 2 11 π ,…. The corresponding y -values are 1, −1, 1, −1, 1, −1,…. At this point we can indeed conclude that lim x →0 sin(1/ x ) does not exist. (Mathematicians frequently abbreviate

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