Calculus Volume 1

Chapter 3 | Derivatives

259

3.19 Find d dx ⎛

⎝ 3 f ( x )−2 g ( x ) ⎞ ⎠ .

Example 3.31 Determining Where a Function Has a Horizontal Tangent

Determine the values of x for which f ( x ) = x 3 −7 x 2 +8 x +1 has a horizontal tangent line.

Solution To find the values of x for which f ( x ) has a horizontal tangent line, we must solve f ′( x ) =0. Since f ′( x ) =3 x 2 −14 x +8= (3 x −2)( x −4), we must solve (3 x −2)( x −4) =0. Thus we see that the function has horizontal tangent lines at x = 2 3 and x =4 as shown in the following graph.

Figure 3.19 This function has horizontal tangent lines at x = 2/3 and x = 4.

Example 3.32 Finding a Velocity The position of an object on a coordinate axis at time t is given by s ( t ) = t t 2 +1

. What is the initial velocity of

the object?

Solution Since the initial velocity is v (0) = s ′(0), begin by finding s ′( t ) by applying the quotient rule:

⎛ ⎝ t 2 +1

⎞ ⎠ −2 t ( t )

1

t 2

s ′( t ) =

= 1−

2 .

2

⎛ ⎝ t 2 +1

⎞ ⎠

⎛ ⎝ t 2 +1

⎞ ⎠

Made with FlippingBook - professional solution for displaying marketing and sales documents online