Calculus Volume 1

Chapter 3 | Derivatives

311

Problem-Solving Strategy: Implicit Differentiation To perform implicit differentiation on an equation that defines a function y implicitly in terms of a variable x , use the following steps: 1. Take the derivative of both sides of the equation. Keep in mind that y is a function of x . Consequently, whereas d dx (sin x ) =cos x , d dx (sin y ) =cos y dy dx because we must use the chain rule to differentiate sin y with respect

to x .

2. Rewrite the equation so that all terms containing dy dx

are on the left and all terms that do not contain dy dx are

on the right.

dy dx

3. Factor out

on the left.

dy dx by dividing both sides of the equation by an appropriate algebraic expression.

4. Solve for

Example 3.68 Using Implicit Differentiation

Assuming that y is defined implicitly by the equation x 2 + y 2 =25, find dy dx .

Solution Follow the steps in the problem-solving strategy. d dx ⎛ ⎝ x 2 + y 2 ⎞ ⎠ = d

dx (25) Step 1. Differentiate both sides of the equation.

Step 1.1. Use the sum rule on the left. On the right d dx (25) =0. Step 1.2. Take the derivatives, so d dx ⎛ ⎝ x 2 ⎞

⎛ ⎝ x 2

⎞ ⎠ + d

⎛ ⎝ y 2

⎞ ⎠ = 0

d dx

dx

⎠ =2 x

dy dx = 0

2 x +2 y

dy dx .

⎛ ⎝ y 2

⎞ ⎠ =2 y

and d

dx

Step 2. Keep the terms with dy dx on the left. Move the remaining terms to the right. Step 4. Divide both sides of the equation by 2 y .(Step 3 does not apply in this case.)

dy dx = −2

2 y

x

dy dx = −

x y

Analysis Note that the resulting expression for

dy dx is in terms of both the independent variable x and the dependent

variable y . Although in some cases it may be possible to express dy dx

in terms of x only, it is generally not

possible to do so.

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