Calculus Volume 1

398

Chapter 4 | Applications of Derivatives

Sign of f ″ ( x ) =6 x −12 at Test Point

Interval

Test Point

Conclusion

(−∞, 2)

x =0

f is concave down

(2, ∞)

x =3

+

f is concave up.

We conclude that f is concave down over the interval (−∞, 2) and concave up over the interval (2, ∞). Since f changes concavity at x =2, the point ⎛ ⎝ 2, f (2) ⎞ ⎠ = (2, 32) is an inflection point. Figure 4.36 confirms the analytical results.

Figure 4.36 The given function has a point of inflection at (2, 32) where the graph changes concavity.

4.18

For f ( x ) =− x 3 + 3 2

x 2 +18 x , find all intervals where f is concave up and all intervals where f is

concave down.

We now summarize, in Table 4.1 , the information that the first and second derivatives of a function f provide about the graph of f , and illustrate this information in Figure 4.37 .

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