Calculus Volume 1

444

Chapter 4 | Applications of Derivatives

Figure 4.66 How can we choose x and y to minimize the travel time from the cabin to the island?

Step 2: The problem is to minimize T . Step 3: To find the time spent traveling from the cabin to the island, add the time spent running and the time spent swimming. Since Distance = Rate × Time ( D = R × T ), the time spent running is T running = = x

D running R running

8 ,

and the time spent swimming is

D swimming R swimming

y 3 .

T swimming =

=

Therefore, the total time spent traveling is

y 3 .

T = x

8 +

Step 4: From Figure 4.66 , the line segment of y miles forms the hypotenuse of a right triangle with legs of length 2mi and 6− x mi. Therefore, by the Pythagorean theorem, 2 2 +(6− x ) 2 = y 2 , and we obtain y = (6− x ) 2 +4. Thus, the total time spent traveling is given by the function T ( x ) = x 8 + (6− x ) 2 +4 3 . Step 5: From Figure 4.66 , we see that 0≤ x ≤6. Therefore, ⎡ ⎣ 0, 6 ⎤ ⎦ is the domain of consideration. Step 6: Since T ( x ) is a continuous function over a closed, bounded interval, it has a maximum and a minimum. Let’s begin by looking for any critical points of T over the interval ⎡ ⎣ 0, 6 ⎤ ⎦ . The derivative is

−1/2

⎡ ⎣ (6− x ) 2 +4 ⎤ ⎦

(6− x ) 3 (6− x ) 2 +4 .

1 2

T ′( x ) = 1

x ) = 1

·2(6−

8 −

3

8 −

If T ′( x ) =0, then

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