Calculus Volume 1

490

Chapter 4 | Applications of Derivatives

if and only if F is an antiderivative of f . Therefore, when claiming that ∫ f ( x ) dx = F ( x )+ C it is important to check whether this statement is correct by verifying that F ′( x ) = f ( x ).

Example 4.51 Verifying an Indefinite Integral Each of the following statements is of the form ∫ f ( x ) dx = F ( x )+ C . Verify that each statement is correct by showing that F ′( x ) = f ( x ). a. ∫ ( x + e x ) dx = x 2 2 + e x + C b. ∫ xe x dx = xe x − e x + C

Solution

a. Since

⎛ ⎝ x 2

⎞ ⎠ = x + e x ,

d dx

e x + C

2 +

the statement

∫ ( x + e x ) dx = x 2

e x + C

2 +

is correct. Note that we are verifying an indefinite integral for a sum. Furthermore, x 2 2 and e x are antiderivatives of x and e x , respectively, and the sum of the antiderivatives is an antiderivative of the sum. We discuss this fact again later in this section. b. Using the product rule, we see that d dx ( xe x − e x + C ) = e x + xe x − e x = xe x .

Therefore, the statement

∫ xe x dx = xe x − e x + C

is correct. Note that we are verifying an indefinite integral for a product. The antiderivative xe x − e x is not a product of the antiderivatives. Furthermore, the product of antiderivatives, x 2 e x /2 is not an antiderivative of xe x since d dx ⎛ ⎝ x 2 e x 2 ⎞ ⎠ = xe x + x 2 e x 2 ≠ xe x .

In general, the product of antiderivatives is not an antiderivative of a product.

This OpenStax book is available for free at http://cnx.org/content/col11964/1.12

Made with FlippingBook - professional solution for displaying marketing and sales documents online