496
Chapter 4 | Applications of Derivatives
Integrating, we have
t 2 +88 t + C .
s ( t ) = − 15 2
Since s (0) =0, the constant is C =0. Therefore, the position function is s ( t ) = − 15 2 t 2 +88 t .
sec, the position is s ⎛
⎞ ⎠ ≈258.133 ft.
⎝ 88 15
After t = 88 15
4.53 Suppose the car is traveling at the rate of 44 ft/sec. How long does it take for the car to stop? How far will the car travel?
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