Chapter 5 | Integration
543
5 x +1 dx = 1 2
∫
h ( a + b )
0
(1+6)
= 1 2 ·5·
= 35 2 .
Thus the average value of the function is 1 5−0 ∫ 0 5
7 2 .
x +1 dx = 1 5
· 35 2 =
Find the average value of f ( x ) =6−2 x over the interval [0, 3].
5.13
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