Calculus Volume 1

604

Chapter 5 | Integration

Then

π /2

sin x 1+cos x =− ∫ 2 1

⌠ ⌡ 0

u −1 du

2

= ∫

u −1 du

1

= ln| u | | 1 2 = [ln2 − ln1] = ln2.

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