Calculus Volume 1

660

Chapter 6 | Applications of Integration

Example 6.13 The Method of Cylindrical Shells 2

Define R as the region bounded above by the graph of f ( x ) =2 x − x 2 and below by the x -axis over the interval [0, 2]. Find the volume of the solid of revolution formed by revolving R around the y -axis.

Solution First graph the region R and the associated solid of revolution, as shown in the following figure.

Figure 6.30 (a) The region R under the graph of f ( x ) =2 x − x 2 over the interval [0, 2]. (b) The volume of revolution obtained by revolving R about the y -axis.

Then the volume of the solid is given by V = ∫ a b ⎛

⎝ 2 πxf ( x ) ⎞

⎠ dx

2 ⎛

2 ⎛

⎝ 2 x 2 − x 3 ⎞

⎛ ⎝ 2 x − x 2 ⎞ ⎠

⎞ ⎠ dx =2 π ∫

= ∫

⎝ 2 πx

⎠ dx

0

0

⎤ ⎦ | 0 2

⎡ ⎣ 2 x 3

x 4 4

= 8 π

3 .

=2 π

3 −

3 units

6.13 Define R as the region bounded above by the graph of f ( x ) =3 x − x 2 and below by the x -axis over the interval [0, 2]. Find the volume of the solid of revolution formed by revolving R around the y -axis.

As with the disk method and the washer method, we can use the method of cylindrical shells with solids of revolution, revolved around the x -axis, when we want to integrate with respect to y . The analogous rule for this type of solid is given here. Rule: The Method of Cylindrical Shells for Solids of Revolution around the x -axis Let g ( y ) be continuous and nonnegative. Define Q as the region bounded on the right by the graph of g ( y ), on the left by the y -axis, below by the line y = c , and above by the line y = d . Then, the volume of the solid of

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