Calculus Volume 1

712

Chapter 6 | Applications of Integration

Solution The region is depicted in the following figure.

Figure 6.70 Finding the centroid of a region between two curves.

The graphs of the functions intersect at (−2, −3) and (1, 0), so we integrate from −2 to 1. Once again, for the sake of convenience, assume ρ =1. First, we need to calculate the total mass: m = ρ ∫ ⎡ ⎣ f ( x )− g ( x ) ⎤ ⎦ dx

a b

1 ⎡

−2 1

⎣ 1− x 2 −( x −1) ⎤

= ∫

⎦ dx = ∫

(2− x 2 − x ) dx

−2

⎦ | −2 1

⎡ ⎣ 2 x − 1 3

x 2 ⎤

⎡ ⎣ 2− 1 3 −

⎤ ⎦ −

⎡ ⎣ −4+ 8 3 −2 ⎤

1 2

x 3 − 1 2

⎦ = 9 2 .

=

=

Next, we compute the moments: M x = ρ ∫ a b

⎛ ⎝ ⎡

⎞ ⎠ dx

1 2

⎤ ⎦ 2 −

⎤ ⎦ 2

⎡ ⎣ g ( x )

⎣ f ( x )

1 ⎛

⎞ ⎠ dx = 1

−2 1 ⎛

2

⎝ ⎛

⎞ ⎠

⎝ x 4 −3 x 2 +2 x ⎞

= 1 2 ∫

2 ∫

⎝ 1− x 2

−( x −1) 2

⎠ dx

−2

⎤ ⎦ | −2 1

⎡ ⎣ x 5 5

− x 3 + x 2

= 1 2

= − 27 10

and

b

M y = ρ ∫

x ⎡ ⎣ f ( x )− g ( x ) ⎤

⎦ dx

a

−2 1

−2 1

⎡ ⎣ (1− x 2 )−( x −1) ⎤

⎡ ⎣ 2− x 2 − x ⎤

= ∫

⎦ dx = ∫

x

x

⎦ dx

−2 1 ⎛

⎝ 2 x − x 4 − x 2 ⎞

= ∫

⎠ dx

⎤ ⎦ | −2 1

⎡ ⎣ x 2 − x

5

3

− x

=

= − 9 4 .

3

5

Therefore, we have

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