Calculus Volume 1

Chapter 6 | Applications of Integration

717

kinds of solids by using the centroid. (There is also a theorem of Pappus for surface area, but it is much less useful than the theorem for volume.)

Theorem 6.14: Theorem of Pappus for Volume Let R be a region in the plane and let l be a line in the plane that does not intersect R . Then the volume of the solid of revolution formed by revolving R around l is equal to the area of R multiplied by the distance d traveled by the centroid of R.

Proof We can prove the case when the region is bounded above by the graph of a function f ( x ) and below by the graph of a function g ( x ) over an interval ⎡ ⎣ a , b ⎤ ⎦ , and for which the axis of revolution is the y -axis. In this case, the area of the region is A = ∫ ⎡ ⎣ f ( x )− g ( x ) ⎤ ⎦ dx . Since the axis of rotation is the y -axis, the distance traveled by the centroid of the region depends

a b

only on the x -coordinate of the centroid, x – , which is

M y

x – =

m ,

where

a b

⎦ dx and M y = ρ ∫ a b x ⎡

m = ρ ∫

⎡ ⎣ f ( x )− g ( x ) ⎤

⎣ f ( x )− g ( x ) ⎤

⎦ dx .

Then,

b

ρ ∫

x ⎡ ⎣ f ( x )− g ( x ) ⎤

⎦ dx

a

d =2 π

a b

ρ ∫

⎡ ⎣ f ( x )− g ( x ) ⎤

⎦ dx

and thus

d · A =2 π ∫ a b

x ⎡ ⎣ f ( x )− g ( x ) ⎤

⎦ dx .

However, using the method of cylindrical shells, we have V =2 π ∫ a b x ⎡

⎣ f ( x )− g ( x ) ⎤

⎦ dx .

So,

V = d · A

and the proof is complete. □ Example 6.34 Using the Theorem of Pappus for Volume

Let R be a circle of radius 2 centered at (4, 0). Use the theorem of Pappus for volume to find the volume of the torus generated by revolving R around the y -axis.

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