Calculus Volume 1

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Chapter 6 | Applications of Integration

d dx

e x = e x

as desired, which leads immediately to the integration formula

∫ e x dx = e x + C .

We apply these formulas in the following examples.

Example 6.38 Using Properties of Exponential Functions

Evaluate the following derivatives: a. d dt e 3 t e t 2

2

d dx

e 3 x

b.

Solution We apply the chain rule as necessary. a. d dt e 3 t e t 2 = d dt e 3 t + t 2 = e 3 t + t 2

(3+2 t )

2

2

d dx

e 3 x

= e 3 x

6 x

b.

6.38

Evaluate the following derivatives:

⎛ ⎝ ⎜ e x

⎞ ⎠ ⎟

2 e 5 x

d dx

a.

3

⎛ ⎝ e 2 t

⎞ ⎠

b. d dt

Example 6.39 Using Properties of Exponential Functions Evaluate the following integral: ∫ 2 xe − x 2 dx .

Solution Using u -substitution, let u =− x 2 . Then du =−2 xdx , and we have ∫ 2 xe − x 2 dx =− ∫ e u du =− e u + C =− e − x 2 + C .

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