Chapter 6 | Applications of Integration
731
Evaluate the following integral: ∫ 3 2 3 x dx .
Solution Use u -substitution and let u =−3 x . Then du =−3 dx and we have ∫ 3 2 3 x dx = ∫ 3·2 −3 x dx =− ∫ 2 u du = − 1 ln2
2 −3 x + C .
2 u + C = − 1 ln2
Evaluate the following integral: ∫ x 2 2 x 3 dx .
6.41
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