Calculus Volume 1

66

Chapter 1 | Functions and Graphs

⎛ ⎝ 15 π 4

⎞ ⎠

c. tan

Solution

corresponds to the point ⎛

⎞ ⎠ . Therefore, sin ⎛

⎞ ⎠ = y = 3

a. On the unit circle, the angle θ = 2 π 3

⎝ 2 π 3

3

⎝ − 1 2 ,

2

2 .

b. An angle θ = − 5 π 6

corresponds to a revolution in the negative direction, as shown. Therefore,

⎛ ⎝ − 5 π 6

⎞ ⎠ = x = − 3 2 .

cos

c. Anangle θ = 15 π

π + 7 π

4 . Therefore, this angle corresponds to more than one revolution, as shown.

4 =2

corresponds to the point ⎛ ⎝ 2

⎞ ⎠ , we can conclude that

Knowing the fact that an angle of 7 π 4

2

2 , −

2

⎛ ⎝ 15 π 4

⎞ ⎠ =

y x =−1.

tan

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