Answer Key
843
−1 ⎛
⎞ ⎠ + C . Taking C =0 recovers the definite integral over ⎡ ⎣ 2, 6 ⎤ ⎦ .
⎝ x 2
The antiderivative is 1
2 sec
419 .
The general antiderivative is tan −1 ( x sin x )+ C . Taking C =−tan −1 (6sin(6)) recovers the definite integral. 421 .
The general antiderivative is tan −1 (ln x )+ C . Taking C = π
−1 ∞
recovers the definite integral.
2 = tan
423 . sin −1 ⎛ ⎝ e ⎠ + C 425 . sin −1 (ln t )+ C 427 . − 1 2 ⎛ ⎝ cos −1 (2 t ) t ⎞ ⎞ ⎠
2
+ C
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