Machinery's Handbook, 31st Edition
2430 Thrust Bearings 1) Internal diameter. Assume D 1 = 7 inches to clear shaft. 2) External diameter. Assume a unit bearing load p a of 400 pounds per square inch from Table 1, then . . , . D 314 09 400 4 70 000 7 17 2 inches 2 2 # # # = + = Round off to 17 inches 3) Radial pad width. a 2 = 17 7 5 inches − = 4) Pitch-line circumference. . . B 2 = 3 14 17 7 37 7 inches + = ^ h 5) Number of pads. Assume groove width of 0.5 inch, then . . . i 5 05 377 685 app = + = Take i = 6. 6) Length of pad . . . . b 6 377 6 05 578inches # = − = 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3 1.4 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 Diameter Ratio, D 1 / D 2 Y S Fig. 11. Oil-Flow Factor, Y G , versus Diameter Ratio D 1 / D 2 —Tapered Land Bearings.* 7) Taper values. Interpolate in Table 2 to obtain . . 0008 0005 inch and inch 1 2 δ δ = = 8) Actual bearing unit load. . , p 6 5 578 70 000 404 psi # # = = * See footnote on page 2418.
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