Machinery's Handbook, 31st Edition
102 RAPID SOLUTION OF RIGHT AND OBLIQUE TRIANGLES Rapid Solution of Right and Oblique Triangles
E 90 ° D =
a 2 = c 2
c a 2 =
b 2
b
b a -
D sin
=
E
b
b
b
90
90
90
90
D
D
c
c
D tan b c = --
c a = --
a b 2 =
c 2
D 90 ° E =
E sin
E
b
b
E
90
90
90
D
90
D
c
c
c
c a E = sin
c a D = cos
b a E = cos
D sin × =
b a
E
E
90
90
b
D
b
90
90
D
c
c
c b D = cot
c b E = tan
E cos = ------
D sin = ------
a b
a b
E
b
b
90
E
90
D
b
b
90
90
c
c
D
b c E = cot
D cos = ------
a c
=-----
a c
b = c
E sin
E
cot D
E
b
b
90
90
D
90
90
D
c
c
c
c
c a E sin D = --s-in-----
D tan a E sin b a E cos =
b a F sin D = --s-i-n----
D 180 ° E F + ( ) =
D
D
D
c
D
F
E
E
F
a
E
a
a
c a E sin D = - -s-i-n--- - - -
F sin b D sin a = ----------
E 180 ° D F + ( ) =
180 ° D E + ( ) = F
D
D
D
c
D
F
E
F
E
F
E
a
a
F sin b D sin a ---------- =
2 c 2 a 2 + 2 bc = ---------------------
D cos b
Area ab E sin 2 =
F 180 ° D E + ( ) =
D
D
b
D
F
E
F
a
E
a
a
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